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21124514002021 is a prime number
BaseRepresentation
bin1001100110110011011110…
…01001110011010001100101
32202210111001200221121022021
410303121233021303101211
510232101001041031041
6112532245011503141
74310124102232033
oct463315711632145
982714050847267
1021124514002021
116804946491631
1224520a4bb7ab1
13ba3057a03741
1453060931d553
1526976ca09cd1
hex13366f273465

21124514002021 has 2 divisors, whose sum is σ = 21124514002022. Its totient is φ = 21124514002020.

The previous prime is 21124514001911. The next prime is 21124514002049. The reversal of 21124514002021 is 12020041542112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12836097562500 + 8288416439521 = 3582750^2 + 2878961^2 .

It is a cyclic number.

It is not a de Polignac number, because 21124514002021 - 215 = 21124513969253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21124514002051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10562257001010 + 10562257001011.

It is an arithmetic number, because the mean of its divisors is an integer number (10562257001011).

Almost surely, 221124514002021 is an apocalyptic number.

It is an amenable number.

21124514002021 is a deficient number, since it is larger than the sum of its proper divisors (1).

21124514002021 is an equidigital number, since it uses as much as digits as its factorization.

21124514002021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 21124514002021 its reverse (12020041542112), we get a palindrome (33144555544133).

The spelling of 21124514002021 in words is "twenty-one trillion, one hundred twenty-four billion, five hundred fourteen million, two thousand, twenty-one".