Base | Representation |
---|---|
bin | 11110101111111001111… |
… | …100011001011111111111 |
3 | 21111000002011020200112221 |
4 | 132233321330121133333 |
5 | 234104432202132312 |
6 | 4254413053110211 |
7 | 305442443136145 |
oct | 36577174313777 |
9 | 7430064220487 |
10 | 2113022302207 |
11 | 745145004313 |
12 | 2a1626a88367 |
13 | 124345c53a7b |
14 | 743b1203595 |
15 | 39e705c2207 |
hex | 1ebf9f197ff |
2113022302207 has 2 divisors, whose sum is σ = 2113022302208. Its totient is φ = 2113022302206.
The previous prime is 2113022302189. The next prime is 2113022302267. The reversal of 2113022302207 is 7022032203112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2113022302207 - 211 = 2113022300159 is a prime.
It is a super-3 number, since 3×21130223022073 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113022302267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056511151103 + 1056511151104.
It is an arithmetic number, because the mean of its divisors is an integer number (1056511151104).
Almost surely, 22113022302207 is an apocalyptic number.
2113022302207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113022302207 is an equidigital number, since it uses as much as digits as its factorization.
2113022302207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 2113022302207 its reverse (7022032203112), we get a palindrome (9135054505319).
The spelling of 2113022302207 in words is "two trillion, one hundred thirteen billion, twenty-two million, three hundred two thousand, two hundred seven".
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