Base | Representation |
---|---|
bin | 1100010011001010111… |
… | …0011010001001001101 |
3 | 202012102011112220222021 |
4 | 3010302232122021031 |
5 | 11430222413032023 |
6 | 241023311050141 |
7 | 21160214653264 |
oct | 3046256321115 |
9 | 665364486867 |
10 | 211304424013 |
11 | 81682925291 |
12 | 34b51510951 |
13 | 16c06333177 |
14 | a3275975db |
15 | 576aae835d |
hex | 3132b9a24d |
211304424013 has 2 divisors, whose sum is σ = 211304424014. Its totient is φ = 211304424012.
The previous prime is 211304423989. The next prime is 211304424029. The reversal of 211304424013 is 310424403112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 206223157924 + 5081266089 = 454118^2 + 71283^2 .
It is a cyclic number.
It is not a de Polignac number, because 211304424013 - 29 = 211304423501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211304424043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105652212006 + 105652212007.
It is an arithmetic number, because the mean of its divisors is an integer number (105652212007).
Almost surely, 2211304424013 is an apocalyptic number.
It is an amenable number.
211304424013 is a deficient number, since it is larger than the sum of its proper divisors (1).
211304424013 is an equidigital number, since it uses as much as digits as its factorization.
211304424013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 211304424013 its reverse (310424403112), we get a palindrome (521728827125).
The spelling of 211304424013 in words is "two hundred eleven billion, three hundred four million, four hundred twenty-four thousand, thirteen".
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