Base | Representation |
---|---|
bin | 11110101111111111010… |
… | …010101111001011000111 |
3 | 21111000022102010001110121 |
4 | 132233333102233023013 |
5 | 234110123140403411 |
6 | 4254430020402411 |
7 | 305444613005536 |
oct | 36577722571307 |
9 | 7430272101417 |
10 | 2113112044231 |
11 | 745190729881 |
12 | 2a1650b46407 |
13 | 12435b715466 |
14 | 743bd0c431d |
15 | 39e783ec571 |
hex | 1ebff4af2c7 |
2113112044231 has 2 divisors, whose sum is σ = 2113112044232. Its totient is φ = 2113112044230.
The previous prime is 2113112044189. The next prime is 2113112044271. The reversal of 2113112044231 is 1324402113112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2113112044231 - 27 = 2113112044103 is a prime.
It is a super-2 number, since 2×21131120442312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2113112044196 and 2113112044205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113112044271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056556022115 + 1056556022116.
It is an arithmetic number, because the mean of its divisors is an integer number (1056556022116).
Almost surely, 22113112044231 is an apocalyptic number.
2113112044231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113112044231 is an equidigital number, since it uses as much as digits as its factorization.
2113112044231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2113112044231 its reverse (1324402113112), we get a palindrome (3437514157343).
The spelling of 2113112044231 in words is "two trillion, one hundred thirteen billion, one hundred twelve million, forty-four thousand, two hundred thirty-one".
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