Base | Representation |
---|---|
bin | 110000000010111110111111… |
… | …000010111110001110001111 |
3 | 1000201012011101220110101120021 |
4 | 300002332333002332032033 |
5 | 210144111021103121221 |
6 | 2025231023250403011 |
7 | 62336511014322442 |
oct | 6002767702761617 |
9 | 1021164356411507 |
10 | 211311301223311 |
11 | 6136a68a736933 |
12 | 1b849667290467 |
13 | 90ba754974a03 |
14 | 3a277431bd659 |
15 | 1966a5a148041 |
hex | c02fbf0be38f |
211311301223311 has 2 divisors, whose sum is σ = 211311301223312. Its totient is φ = 211311301223310.
The previous prime is 211311301223227. The next prime is 211311301223377. The reversal of 211311301223311 is 113322103113112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211311301223311 - 217 = 211311301092239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211311301220311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105655650611655 + 105655650611656.
It is an arithmetic number, because the mean of its divisors is an integer number (105655650611656).
Almost surely, 2211311301223311 is an apocalyptic number.
211311301223311 is a deficient number, since it is larger than the sum of its proper divisors (1).
211311301223311 is an equidigital number, since it uses as much as digits as its factorization.
211311301223311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 211311301223311 its reverse (113322103113112), we get a palindrome (324633404336423).
The spelling of 211311301223311 in words is "two hundred eleven trillion, three hundred eleven billion, three hundred one million, two hundred twenty-three thousand, three hundred eleven".
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