Base | Representation |
---|---|
bin | 110000000010111110111111… |
… | …101001001001010000110000 |
3 | 1000201012011102121021210011101 |
4 | 300002332333221021100300 |
5 | 210144111031133330000 |
6 | 2025231024245054144 |
7 | 62336511165350452 |
oct | 6002767751112060 |
9 | 1021164377253141 |
10 | 211311311230000 |
11 | 6136a695351023 |
12 | 1b84966a6b7354 |
13 | 90ba756a69627 |
14 | 3a277446662d2 |
15 | 1966a5ae72e6a |
hex | c02fbfa49430 |
211311311230000 has 100 divisors (see below), whose sum is σ = 511639674145600. Its totient is φ = 84518930592000.
The previous prime is 211311311229961. The next prime is 211311311230007. The reversal of 211311311230000 is 32113113112.
It is a tau number, because it is divible by the number of its divisors (100).
It is a super-2 number, since 2×2113113112300002 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211311311230000.
It is not an unprimeable number, because it can be changed into a prime (211311311230007) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 152078401 + ... + 153461599.
It is an arithmetic number, because the mean of its divisors is an integer number (5116396741456).
Almost surely, 2211311311230000 is an apocalyptic number.
211311311230000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211311311230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (255819837072800).
211311311230000 is an abundant number, since it is smaller than the sum of its proper divisors (300328362915600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211311311230000 is a wasteful number, since it uses less digits than its factorization.
211311311230000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1398504 (or 1398483 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 211311311230000 its reverse (32113113112), we get a palindrome (211343424343112).
The spelling of 211311311230000 in words is "two hundred eleven trillion, three hundred eleven billion, three hundred eleven million, two hundred thirty thousand".
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