Base | Representation |
---|---|
bin | 110000000011000001100010… |
… | …010011110001010100110110 |
3 | 1000201012102110210112120102210 |
4 | 300003001202103301110312 |
5 | 210144132123310010032 |
6 | 2025232155134514250 |
7 | 62336635624233204 |
oct | 6003014223612466 |
9 | 1021172423476383 |
10 | 211314040313142 |
11 | 613708658a1638 |
12 | 1b84a0b0665986 |
13 | 90baaa0296920 |
14 | 3a27922caa074 |
15 | 1966b6a8502cc |
hex | c030624f1536 |
211314040313142 has 32 divisors (see below), whose sum is σ = 455144716051200. Its totient is φ = 65018735701920.
The previous prime is 211314040313111. The next prime is 211314040313171. The reversal of 211314040313142 is 241313040413112.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14911642 + ... + 25396557.
It is an arithmetic number, because the mean of its divisors is an integer number (14223272376600).
Almost surely, 2211314040313142 is an apocalyptic number.
211314040313142 is an abundant number, since it is smaller than the sum of its proper divisors (243830675738058).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211314040313142 is a wasteful number, since it uses less digits than its factorization.
211314040313142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40375428.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 211314040313142 its reverse (241313040413112), we get a palindrome (452627080726254).
The spelling of 211314040313142 in words is "two hundred eleven trillion, three hundred fourteen billion, forty million, three hundred thirteen thousand, one hundred forty-two".
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