Base | Representation |
---|---|
bin | 1001100111000000010110… |
… | …11100110111010001000111 |
3 | 2202211010220202220021200021 |
4 | 10303200023130313101013 |
5 | 10232204132342241403 |
6 | 112535351231400011 |
7 | 4310460364445212 |
oct | 463401334672107 |
9 | 82733822807607 |
10 | 21131431212103 |
11 | 6807876029983 |
12 | 24534b5683007 |
13 | ba38bab10464 |
14 | 530aa3c88779 |
15 | 269a24e1d8bd |
hex | 13380b737447 |
21131431212103 has 2 divisors, whose sum is σ = 21131431212104. Its totient is φ = 21131431212102.
The previous prime is 21131431212097. The next prime is 21131431212107. The reversal of 21131431212103 is 30121213413112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21131431212103 - 221 = 21131429114951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21131431212107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10565715606051 + 10565715606052.
It is an arithmetic number, because the mean of its divisors is an integer number (10565715606052).
Almost surely, 221131431212103 is an apocalyptic number.
21131431212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21131431212103 is an equidigital number, since it uses as much as digits as its factorization.
21131431212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 21131431212103 its reverse (30121213413112), we get a palindrome (51252644625215).
The spelling of 21131431212103 in words is "twenty-one trillion, one hundred thirty-one billion, four hundred thirty-one million, two hundred twelve thousand, one hundred three".
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