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21131440000 = 27541123759
BaseRepresentation
bin10011101011100010…
…000010111110000000
32000112200112101010221
4103223202002332000
5321234122040000
613412504032424
71345441163536
oct235342027600
960480471127
1021131440000
118a64168700
124118a62714
131cb9c15b68
14104668a156
1583a26261a
hex4eb882f80

21131440000 has 480 divisors, whose sum is σ = 60391762200. Its totient is φ = 7349760000.

The previous prime is 21131439929. The next prime is 21131440019. The reversal of 21131440000 is 4413112.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 358159971 + ... + 358160029.

Almost surely, 221131440000 is an apocalyptic number.

21131440000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21131440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (30195881100).

21131440000 is an abundant number, since it is smaller than the sum of its proper divisors (39260322200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21131440000 is an equidigital number, since it uses as much as digits as its factorization.

21131440000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 152 (or 114 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 21131440000 its reverse (4413112), we get a palindrome (21135853112).

The spelling of 21131440000 in words is "twenty-one billion, one hundred thirty-one million, four hundred forty thousand".