Base | Representation |
---|---|
bin | 110000000011000011101111… |
… | …010000011100110111111111 |
3 | 1000201012122120121011122200102 |
4 | 300003003233100130313333 |
5 | 210144201444141433044 |
6 | 2025233225530551315 |
7 | 62340051340056464 |
oct | 6003035720346777 |
9 | 1021178517148612 |
10 | 211316405030399 |
11 | 613718696a5719 |
12 | 1b84a65059853b |
13 | 90bb08917abc6 |
14 | 3a27aa8d8366b |
15 | 1966c5825724e |
hex | c030ef41cdff |
211316405030399 has 2 divisors, whose sum is σ = 211316405030400. Its totient is φ = 211316405030398.
The previous prime is 211316405030309. The next prime is 211316405030411. The reversal of 211316405030399 is 993030504613112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211316405030399 - 212 = 211316405026303 is a prime.
It is a super-2 number, since 2×2113164050303992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211316405030309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105658202515199 + 105658202515200.
It is an arithmetic number, because the mean of its divisors is an integer number (105658202515200).
Almost surely, 2211316405030399 is an apocalyptic number.
211316405030399 is a deficient number, since it is larger than the sum of its proper divisors (1).
211316405030399 is an equidigital number, since it uses as much as digits as its factorization.
211316405030399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 47.
The spelling of 211316405030399 in words is "two hundred eleven trillion, three hundred sixteen billion, four hundred five million, thirty thousand, three hundred ninety-nine".
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