Base | Representation |
---|---|
bin | 1100010011001110101… |
… | …0010000001110000010 |
3 | 202012110021001221211220 |
4 | 3010303222100032002 |
5 | 11430240422041002 |
6 | 241025031215510 |
7 | 21160465212666 |
oct | 3046352201602 |
9 | 665407057756 |
10 | 211320112002 |
11 | 8169076a96a |
12 | 34b56817596 |
13 | 16c096669bc |
14 | a3296bc8a6 |
15 | 576c1967bc |
hex | 3133a90382 |
211320112002 has 32 divisors (see below), whose sum is σ = 444937732800. Its totient is φ = 66724674048.
The previous prime is 211320112001. The next prime is 211320112013. The reversal of 211320112002 is 200211023112.
It is a super-4 number, since 4×2113201120024 (a number of 46 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (211320112001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 883878 + ... + 1097214.
It is an arithmetic number, because the mean of its divisors is an integer number (13904304150).
Almost surely, 2211320112002 is an apocalyptic number.
211320112002 is an abundant number, since it is smaller than the sum of its proper divisors (233617620798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211320112002 is a wasteful number, since it uses less digits than its factorization.
211320112002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222050.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 211320112002 its reverse (200211023112), we get a palindrome (411531135114).
The spelling of 211320112002 in words is "two hundred eleven billion, three hundred twenty million, one hundred twelve thousand, two".
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