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2113201337101 is a prime number
BaseRepresentation
bin11110110000000100100…
…111010111001100001101
321111000112122010121020221
4132300010213113030031
5234110314020241401
64254442530311341
7305450045664601
oct36600447271415
97430478117227
102113201337101
11745227077938
122a1676a28551
1312437407a58a
14743cacc9501
1539e811897a1
hex1ec049d730d

2113201337101 has 2 divisors, whose sum is σ = 2113201337102. Its totient is φ = 2113201337100.

The previous prime is 2113201336997. The next prime is 2113201337147. The reversal of 2113201337101 is 1017331023112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1551833267076 + 561368070025 = 1245726^2 + 749245^2 .

It is a cyclic number.

It is not a de Polignac number, because 2113201337101 - 211 = 2113201335053 is a prime.

It is a super-3 number, since 3×21132013371013 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113201307101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056600668550 + 1056600668551.

It is an arithmetic number, because the mean of its divisors is an integer number (1056600668551).

Almost surely, 22113201337101 is an apocalyptic number.

It is an amenable number.

2113201337101 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113201337101 is an equidigital number, since it uses as much as digits as its factorization.

2113201337101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

The spelling of 2113201337101 in words is "two trillion, one hundred thirteen billion, two hundred one million, three hundred thirty-seven thousand, one hundred one".