Base | Representation |
---|---|
bin | 1100010011010001100… |
… | …0000100100110100111 |
3 | 202012111002200011220102 |
4 | 3010310120010212213 |
5 | 11430302010414142 |
6 | 241030140454315 |
7 | 21161002256423 |
oct | 3046430044647 |
9 | 665432604812 |
10 | 211332123047 |
11 | 81697523a51 |
12 | 34b5a84a39b |
13 | 16c0bcb0a26 |
14 | a32b127b83 |
15 | 576d26a532 |
hex | 31346049a7 |
211332123047 has 2 divisors, whose sum is σ = 211332123048. Its totient is φ = 211332123046.
The previous prime is 211332123011. The next prime is 211332123049. The reversal of 211332123047 is 740321233112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211332123047 - 26 = 211332122983 is a prime.
It is a super-2 number, since 2×2113321230472 (a number of 23 digits) contains 22 as substring.
Together with 211332123049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211332123049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105666061523 + 105666061524.
It is an arithmetic number, because the mean of its divisors is an integer number (105666061524).
Almost surely, 2211332123047 is an apocalyptic number.
211332123047 is a deficient number, since it is larger than the sum of its proper divisors (1).
211332123047 is an equidigital number, since it uses as much as digits as its factorization.
211332123047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 211332123047 its reverse (740321233112), we get a palindrome (951653356159).
The spelling of 211332123047 in words is "two hundred eleven billion, three hundred thirty-two million, one hundred twenty-three thousand, forty-seven".
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