Base | Representation |
---|---|
bin | 11110110000001011111… |
… | …100011110111011000111 |
3 | 21111000212012112111021102 |
4 | 132300023330132323013 |
5 | 234111042011024221 |
6 | 4254503042210315 |
7 | 305453101166000 |
oct | 36601374367307 |
9 | 7430765474242 |
10 | 2113324314311 |
11 | 74528a5324a1 |
12 | 2a16b005399b |
13 | 1243936a7662 |
14 | 743dd37c1a7 |
15 | 39e8bd7c30b |
hex | 1ec0bf1eec7 |
2113324314311 has 64 divisors (see below), whose sum is σ = 2638340812800. Its totient is φ = 1689392113920.
The previous prime is 2113324314307. The next prime is 2113324314319. The reversal of 2113324314311 is 1134134233112.
It is not a de Polignac number, because 2113324314311 - 22 = 2113324314307 is a prime.
It is a super-2 number, since 2×21133243143112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2113324314319) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28384145 + ... + 28458501.
It is an arithmetic number, because the mean of its divisors is an integer number (41224075200).
Almost surely, 22113324314311 is an apocalyptic number.
2113324314311 is a deficient number, since it is larger than the sum of its proper divisors (525016498489).
2113324314311 is an equidigital number, since it uses as much as digits as its factorization.
2113324314311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74509 (or 74495 counting only the distinct ones).
The product of its digits is 5184, while the sum is 29.
Adding to 2113324314311 its reverse (1134134233112), we get a palindrome (3247458547423).
The spelling of 2113324314311 in words is "two trillion, one hundred thirteen billion, three hundred twenty-four million, three hundred fourteen thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •