Base | Representation |
---|---|
bin | 110000000011010011100000… |
… | …000100100101100000111000 |
3 | 1000201021021021010201211221020 |
4 | 300003103200010211200320 |
5 | 210144441130003143000 |
6 | 2025245105214342440 |
7 | 62341220634050220 |
oct | 6003234004454070 |
9 | 1021237233654836 |
10 | 211333330131000 |
11 | 61378a64457270 |
12 | 1b8519947baa20 |
13 | 90bc8557a872c |
14 | 3a28832b27080 |
15 | 19673e9086ba0 |
hex | c034e0125838 |
211333330131000 has 1024 divisors, whose sum is σ = 865889077248000. Its totient is φ = 41575092480000.
The previous prime is 211333330130903. The next prime is 211333330131013. The reversal of 211333330131000 is 131033333112.
It is a super-2 number, since 2×2113333301310002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 7105776130 + ... + 7105805870.
It is an arithmetic number, because the mean of its divisors is an integer number (845594802000).
Almost surely, 2211333330131000 is an apocalyptic number.
211333330131000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211333330131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (432944538624000).
211333330131000 is an abundant number, since it is smaller than the sum of its proper divisors (654555747117000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211333330131000 is a wasteful number, since it uses less digits than its factorization.
211333330131000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31421 (or 31407 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 211333330131000 its reverse (131033333112), we get a palindrome (211464363464112).
The spelling of 211333330131000 in words is "two hundred eleven trillion, three hundred thirty-three billion, three hundred thirty million, one hundred thirty-one thousand".
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