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211351553400973 is a prime number
BaseRepresentation
bin110000000011100100011110…
…010000110110000010001101
31000201100000022011000212210011
4300003210132100312002031
5210200240440132312343
62025301321354313221
762342434343225206
oct6003443620660215
91021300264025704
10211351553400973
1161385765a75767
121b85541b728811
1390c149b04cc0b
143a296810725ad
151967b13d4429d
hexc0391e43608d

211351553400973 has 2 divisors, whose sum is σ = 211351553400974. Its totient is φ = 211351553400972.

The previous prime is 211351553400971. The next prime is 211351553401049. The reversal of 211351553400973 is 379004355153112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 208138271292004 + 3213282108969 = 14426998^2 + 1792563^2 .

It is a cyclic number.

It is not a de Polignac number, because 211351553400973 - 21 = 211351553400971 is a prime.

Together with 211351553400971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211351553400971) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105675776700486 + 105675776700487.

It is an arithmetic number, because the mean of its divisors is an integer number (105675776700487).

Almost surely, 2211351553400973 is an apocalyptic number.

It is an amenable number.

211351553400973 is a deficient number, since it is larger than the sum of its proper divisors (1).

211351553400973 is an equidigital number, since it uses as much as digits as its factorization.

211351553400973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1701000, while the sum is 49.

The spelling of 211351553400973 in words is "two hundred eleven trillion, three hundred fifty-one billion, five hundred fifty-three million, four hundred thousand, nine hundred seventy-three".