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211402013 is a prime number
BaseRepresentation
bin11001001100110…
…11110100011101
3112201210100001012
430212123310131
5413104331023
632551025005
75144613254
oct1446336435
9481710035
10211402013
11a9370509
125a96b165
1334a4a064
142010d79b
151385c978
hexc99bd1d

211402013 has 2 divisors, whose sum is σ = 211402014. Its totient is φ = 211402012.

The previous prime is 211402007. The next prime is 211402019. The reversal of 211402013 is 310204112.

It is a balanced prime because it is at equal distance from previous prime (211402007) and next prime (211402019).

It can be written as a sum of positive squares in only one way, i.e., 168013444 + 43388569 = 12962^2 + 6587^2 .

It is a cyclic number.

It is not a de Polignac number, because 211402013 - 218 = 211139869 is a prime.

It is a super-2 number, since 2×2114020132 = 89381622200904338, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211402019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105701006 + 105701007.

It is an arithmetic number, because the mean of its divisors is an integer number (105701007).

Almost surely, 2211402013 is an apocalyptic number.

It is an amenable number.

211402013 is a deficient number, since it is larger than the sum of its proper divisors (1).

211402013 is an equidigital number, since it uses as much as digits as its factorization.

211402013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 211402013 is about 14539.6703195086. The cubic root of 211402013 is about 595.7120331988.

Adding to 211402013 its reverse (310204112), we get a palindrome (521606125).

The spelling of 211402013 in words is "two hundred eleven million, four hundred two thousand, thirteen".