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21140525340281 is a prime number
BaseRepresentation
bin1001100111010001010011…
…00000001101011001111001
32202212000101120002212021102
410303220221200031121321
510232331243441342111
6112543453454221145
74311231632324354
oct463505140153171
982760346085242
1021140525340281
116810712470a96
1224552131b47b5
13ba4709c296a9
145312c79a329b
15269da84e013b
hex133a2980d679

21140525340281 has 2 divisors, whose sum is σ = 21140525340282. Its totient is φ = 21140525340280.

The previous prime is 21140525340271. The next prime is 21140525340331. The reversal of 21140525340281 is 18204352504112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12643393620025 + 8497131720256 = 3555755^2 + 2914984^2 .

It is a cyclic number.

It is not a de Polignac number, because 21140525340281 - 218 = 21140525078137 is a prime.

It is a super-2 number, since 2×211405253402812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21140525340271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570262670140 + 10570262670141.

It is an arithmetic number, because the mean of its divisors is an integer number (10570262670141).

Almost surely, 221140525340281 is an apocalyptic number.

It is an amenable number.

21140525340281 is a deficient number, since it is larger than the sum of its proper divisors (1).

21140525340281 is an equidigital number, since it uses as much as digits as its factorization.

21140525340281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 38.

Adding to 21140525340281 its reverse (18204352504112), we get a palindrome (39344877844393).

The spelling of 21140525340281 in words is "twenty-one trillion, one hundred forty billion, five hundred twenty-five million, three hundred forty thousand, two hundred eighty-one".