Base | Representation |
---|---|
bin | 1001100111010001010011… |
… | …00000001101011010101011 |
3 | 2202212000101120002212100021 |
4 | 10303220221200031122223 |
5 | 10232331243441342311 |
6 | 112543453454221311 |
7 | 4311231632324455 |
oct | 463505140153253 |
9 | 82760346085307 |
10 | 21140525340331 |
11 | 6810712471031 |
12 | 24552131b4837 |
13 | ba4709c29717 |
14 | 5312c79a32d5 |
15 | 269da84e0171 |
hex | 133a2980d6ab |
21140525340331 has 2 divisors, whose sum is σ = 21140525340332. Its totient is φ = 21140525340330.
The previous prime is 21140525340281. The next prime is 21140525340349. The reversal of 21140525340331 is 13304352504112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21140525340331 - 215 = 21140525307563 is a prime.
It is a super-2 number, since 2×211405253403312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21140525340031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570262670165 + 10570262670166.
It is an arithmetic number, because the mean of its divisors is an integer number (10570262670166).
Almost surely, 221140525340331 is an apocalyptic number.
21140525340331 is a deficient number, since it is larger than the sum of its proper divisors (1).
21140525340331 is an equidigital number, since it uses as much as digits as its factorization.
21140525340331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 21140525340331 its reverse (13304352504112), we get a palindrome (34444877844443).
The spelling of 21140525340331 in words is "twenty-one trillion, one hundred forty billion, five hundred twenty-five million, three hundred forty thousand, three hundred thirty-one".
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