Base | Representation |
---|---|
bin | 1100010011100100000… |
… | …1100111001000001111 |
3 | 202012200112102220022001 |
4 | 3010321001213020033 |
5 | 11430431442334411 |
6 | 241042004333131 |
7 | 21162640244401 |
oct | 3047101471017 |
9 | 665615386261 |
10 | 211410121231 |
11 | 81727558161 |
12 | 34b809a41a7 |
13 | 16c221bcbba |
14 | a33762cb71 |
15 | 5775025dc1 |
hex | 313906720f |
211410121231 has 2 divisors, whose sum is σ = 211410121232. Its totient is φ = 211410121230.
The previous prime is 211410121201. The next prime is 211410121243. The reversal of 211410121231 is 132121014112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211410121231 - 219 = 211409596943 is a prime.
It is a super-2 number, since 2×2114101212312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211410121199 and 211410121208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211410121201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705060615 + 105705060616.
It is an arithmetic number, because the mean of its divisors is an integer number (105705060616).
Almost surely, 2211410121231 is an apocalyptic number.
211410121231 is a deficient number, since it is larger than the sum of its proper divisors (1).
211410121231 is an equidigital number, since it uses as much as digits as its factorization.
211410121231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 211410121231 its reverse (132121014112), we get a palindrome (343531135343).
The spelling of 211410121231 in words is "two hundred eleven billion, four hundred ten million, one hundred twenty-one thousand, two hundred thirty-one".
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