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211411324231 is a prime number
BaseRepresentation
bin1100010011100100011…
…0001100110101000111
3202012200121201000111121
43010321012030311013
511430432244333411
6241042050214411
721162653414602
oct3047106146507
9665617630447
10211411324231
11817281a9a78
1234b81284407
1316c22521633
14a337863339
1557751b2571
hex313918cd47

211411324231 has 2 divisors, whose sum is σ = 211411324232. Its totient is φ = 211411324230.

The previous prime is 211411324133. The next prime is 211411324259. The reversal of 211411324231 is 132423114112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211411324231 is a prime.

It is a super-2 number, since 2×2114113242312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211411324196 and 211411324205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211411124231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105705662115 + 105705662116.

It is an arithmetic number, because the mean of its divisors is an integer number (105705662116).

Almost surely, 2211411324231 is an apocalyptic number.

211411324231 is a deficient number, since it is larger than the sum of its proper divisors (1).

211411324231 is an equidigital number, since it uses as much as digits as its factorization.

211411324231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 25.

Adding to 211411324231 its reverse (132423114112), we get a palindrome (343834438343).

The spelling of 211411324231 in words is "two hundred eleven billion, four hundred eleven million, three hundred twenty-four thousand, two hundred thirty-one".