21141230111 has 2 divisors, whose sum is σ = 21141230112. Its totient is φ = 21141230110.

The previous prime is 21141230101. The next prime is 21141230113. The reversal of 21141230111 is 11103214112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21141230111 is a prime.

It is a super-2 number, since 2×21141230111² (a number of 21 digits) contains 22 as substring.

Together with 21141230113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21141230111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21141230113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570615055 + 10570615056.

It is an arithmetic number, because the mean of its divisors is an integer number (10570615056).

Almost surely, 2^21141230111 is an apocalyptic number.

21141230111 is a deficient number, since it is larger than the sum of its proper divisors (1).

21141230111 is an equidigital number, since it uses as much as digits as its factorization.

21141230111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 21141230111 its reverse (11103214112), we get a palindrome (32244444223).

The spelling of 21141230111 in words is "twenty-one billion, one hundred forty-one million, two hundred thirty thousand, one hundred eleven".