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21141431021 is a prime number
BaseRepresentation
bin10011101100001000…
…001010001011101101
32000120101022222020202
4103230020022023231
5321244201243041
613413502123245
71345622125064
oct235410121355
960511288222
1021141431021
118a69872047
124120280525
131cbc0035c9
141047b2b1db
1583b087a9b
hex4ec20a2ed

21141431021 has 2 divisors, whose sum is σ = 21141431022. Its totient is φ = 21141431020.

The previous prime is 21141431011. The next prime is 21141431023. The reversal of 21141431021 is 12013414112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20411836900 + 729594121 = 142870^2 + 27011^2 .

It is a cyclic number.

It is not a de Polignac number, because 21141431021 - 218 = 21141168877 is a prime.

It is a super-2 number, since 2×211414310212 (a number of 21 digits) contains 22 as substring.

Together with 21141431023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21141430984 and 21141431002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21141431023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10570715510 + 10570715511.

It is an arithmetic number, because the mean of its divisors is an integer number (10570715511).

Almost surely, 221141431021 is an apocalyptic number.

It is an amenable number.

21141431021 is a deficient number, since it is larger than the sum of its proper divisors (1).

21141431021 is an equidigital number, since it uses as much as digits as its factorization.

21141431021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 21141431021 its reverse (12013414112), we get a palindrome (33154845133).

The spelling of 21141431021 in words is "twenty-one billion, one hundred forty-one million, four hundred thirty-one thousand, twenty-one".