Base | Representation |
---|---|
bin | 1100010011100110011… |
… | …1111010111110111111 |
3 | 202012201020100010102121 |
4 | 3010321213322332333 |
5 | 11430442030222111 |
6 | 241043003503411 |
7 | 21163121512606 |
oct | 3047147727677 |
9 | 665636303377 |
10 | 211420164031 |
11 | 8173219749a |
12 | 34b84227b67 |
13 | 16c242c809b |
14 | a338ac4a3d |
15 | 5775d5b871 |
hex | 31399fafbf |
211420164031 has 2 divisors, whose sum is σ = 211420164032. Its totient is φ = 211420164030.
The previous prime is 211420163993. The next prime is 211420164037. The reversal of 211420164031 is 130461024112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211420164031 - 213 = 211420155839 is a prime.
It is a super-2 number, since 2×2114201640312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211420163987 and 211420164005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211420164037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105710082015 + 105710082016.
It is an arithmetic number, because the mean of its divisors is an integer number (105710082016).
Almost surely, 2211420164031 is an apocalyptic number.
211420164031 is a deficient number, since it is larger than the sum of its proper divisors (1).
211420164031 is an equidigital number, since it uses as much as digits as its factorization.
211420164031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 211420164031 its reverse (130461024112), we get a palindrome (341881188143).
The spelling of 211420164031 in words is "two hundred eleven billion, four hundred twenty million, one hundred sixty-four thousand, thirty-one".
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