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211420164031 is a prime number
BaseRepresentation
bin1100010011100110011…
…1111010111110111111
3202012201020100010102121
43010321213322332333
511430442030222111
6241043003503411
721163121512606
oct3047147727677
9665636303377
10211420164031
118173219749a
1234b84227b67
1316c242c809b
14a338ac4a3d
155775d5b871
hex31399fafbf

211420164031 has 2 divisors, whose sum is σ = 211420164032. Its totient is φ = 211420164030.

The previous prime is 211420163993. The next prime is 211420164037. The reversal of 211420164031 is 130461024112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 211420164031 - 213 = 211420155839 is a prime.

It is a super-2 number, since 2×2114201640312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211420163987 and 211420164005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211420164037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105710082015 + 105710082016.

It is an arithmetic number, because the mean of its divisors is an integer number (105710082016).

Almost surely, 2211420164031 is an apocalyptic number.

211420164031 is a deficient number, since it is larger than the sum of its proper divisors (1).

211420164031 is an equidigital number, since it uses as much as digits as its factorization.

211420164031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 211420164031 its reverse (130461024112), we get a palindrome (341881188143).

The spelling of 211420164031 in words is "two hundred eleven billion, four hundred twenty million, one hundred sixty-four thousand, thirty-one".