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2114210221421 is a prime number
BaseRepresentation
bin11110110001000000101…
…111111100110101101101
321111010010221112020100212
4132301000233330311231
5234114400304041141
64255131010232205
7305514046240364
oct36610057746555
97433127466325
102114210221421
117456a4609631
122a18b8885665
131244a50a854c
1474484caa7db
1539edea232eb
hex1ec40bfcd6d

2114210221421 has 2 divisors, whose sum is σ = 2114210221422. Its totient is φ = 2114210221420.

The previous prime is 2114210221399. The next prime is 2114210221423. The reversal of 2114210221421 is 1241220124112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2114156712196 + 53509225 = 1454014^2 + 7315^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2114210221421 is a prime.

It is a super-2 number, since 2×21142102214212 (a number of 25 digits) contains 22 as substring.

Together with 2114210221423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2114210221423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057105110710 + 1057105110711.

It is an arithmetic number, because the mean of its divisors is an integer number (1057105110711).

Almost surely, 22114210221421 is an apocalyptic number.

It is an amenable number.

2114210221421 is a deficient number, since it is larger than the sum of its proper divisors (1).

2114210221421 is an equidigital number, since it uses as much as digits as its factorization.

2114210221421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 2114210221421 its reverse (1241220124112), we get a palindrome (3355430345533).

The spelling of 2114210221421 in words is "two trillion, one hundred fourteen billion, two hundred ten million, two hundred twenty-one thousand, four hundred twenty-one".