Base | Representation |
---|---|
bin | 1100010011100111001… |
… | …1001111011001010111 |
3 | 202012201102220212122121 |
4 | 3010321303033121113 |
5 | 11430443310144343 |
6 | 241043151240411 |
7 | 21163155651403 |
oct | 3047163173127 |
9 | 665642825577 |
10 | 211423131223 |
11 | 81733933817 |
12 | 34b85219107 |
13 | 16c24ac6815 |
14 | a339258103 |
15 | 5776245aed |
hex | 3139ccf657 |
211423131223 has 2 divisors, whose sum is σ = 211423131224. Its totient is φ = 211423131222.
The previous prime is 211423131211. The next prime is 211423131247. The reversal of 211423131223 is 322131324112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211423131223 is a prime.
It is a super-2 number, since 2×2114231312232 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211423131253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105711565611 + 105711565612.
It is an arithmetic number, because the mean of its divisors is an integer number (105711565612).
Almost surely, 2211423131223 is an apocalyptic number.
211423131223 is a deficient number, since it is larger than the sum of its proper divisors (1).
211423131223 is an equidigital number, since it uses as much as digits as its factorization.
211423131223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 25.
Adding to 211423131223 its reverse (322131324112), we get a palindrome (533554455335).
The spelling of 211423131223 in words is "two hundred eleven billion, four hundred twenty-three million, one hundred thirty-one thousand, two hundred twenty-three".
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