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211423201333 is a prime number
BaseRepresentation
bin1100010011100111001…
…1100000100000110101
3202012201110001102211021
43010321303200200311
511430443314420313
6241043152541141
721163156362661
oct3047163404065
9665643042737
10211423201333
1181733981463
1234b852517b1
1316c24b1c6c6
14a3392758a1
15577625b78d
hex3139ce0835

211423201333 has 2 divisors, whose sum is σ = 211423201334. Its totient is φ = 211423201332.

The previous prime is 211423201303. The next prime is 211423201357. The reversal of 211423201333 is 333102324112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174408134884 + 37015066449 = 417622^2 + 192393^2 .

It is a cyclic number.

It is not a de Polignac number, because 211423201333 - 213 = 211423193141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211423201298 and 211423201307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211423201303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105711600666 + 105711600667.

It is an arithmetic number, because the mean of its divisors is an integer number (105711600667).

Almost surely, 2211423201333 is an apocalyptic number.

It is an amenable number.

211423201333 is a deficient number, since it is larger than the sum of its proper divisors (1).

211423201333 is an equidigital number, since it uses as much as digits as its factorization.

211423201333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 211423201333 its reverse (333102324112), we get a palindrome (544525525445).

The spelling of 211423201333 in words is "two hundred eleven billion, four hundred twenty-three million, two hundred one thousand, three hundred thirty-three".