Base | Representation |
---|---|
bin | 1100010011101001001… |
… | …0111001111101001101 |
3 | 202012202000112121012021 |
4 | 3010322102321331031 |
5 | 11431002421311023 |
6 | 241044045210141 |
7 | 21163316343064 |
oct | 3047222717515 |
9 | 665660477167 |
10 | 211431432013 |
11 | 8173859327a |
12 | 34b87b60951 |
13 | 16c26741b29 |
14 | a33a3b91db |
15 | 5776d3535d |
hex | 313a4b9f4d |
211431432013 has 2 divisors, whose sum is σ = 211431432014. Its totient is φ = 211431432012.
The previous prime is 211431432001. The next prime is 211431432041. The reversal of 211431432013 is 310234134112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115815660489 + 95615771524 = 340317^2 + 309218^2 .
It is a cyclic number.
It is not a de Polignac number, because 211431432013 - 237 = 73992478541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211431430013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105715716006 + 105715716007.
It is an arithmetic number, because the mean of its divisors is an integer number (105715716007).
Almost surely, 2211431432013 is an apocalyptic number.
It is an amenable number.
211431432013 is a deficient number, since it is larger than the sum of its proper divisors (1).
211431432013 is an equidigital number, since it uses as much as digits as its factorization.
211431432013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 211431432013 its reverse (310234134112), we get a palindrome (521665566125).
The spelling of 211431432013 in words is "two hundred eleven billion, four hundred thirty-one million, four hundred thirty-two thousand, thirteen".
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