Base | Representation |
---|---|
bin | 1100010011111111100… |
… | …1010111110111001101 |
3 | 202012222120100202212102 |
4 | 3010333321113313031 |
5 | 11431201000331221 |
6 | 241101243244445 |
7 | 21165540152201 |
oct | 3047771276715 |
9 | 665876322772 |
10 | 211525402061 |
11 | 81786636376 |
12 | 34bb3519725 |
13 | 16c40053acc |
14 | a348a7ab01 |
15 | 57801e830b |
hex | 313fe57dcd |
211525402061 has 2 divisors, whose sum is σ = 211525402062. Its totient is φ = 211525402060.
The previous prime is 211525402057. The next prime is 211525402063. The reversal of 211525402061 is 160204525112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199032869161 + 12492532900 = 446131^2 + 111770^2 .
It is a cyclic number.
It is not a de Polignac number, because 211525402061 - 22 = 211525402057 is a prime.
Together with 211525402063, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211525402063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105762701030 + 105762701031.
It is an arithmetic number, because the mean of its divisors is an integer number (105762701031).
Almost surely, 2211525402061 is an apocalyptic number.
It is an amenable number.
211525402061 is a deficient number, since it is larger than the sum of its proper divisors (1).
211525402061 is an equidigital number, since it uses as much as digits as its factorization.
211525402061 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 29.
Adding to 211525402061 its reverse (160204525112), we get a palindrome (371729927173).
The spelling of 211525402061 in words is "two hundred eleven billion, five hundred twenty-five million, four hundred two thousand, sixty-one".
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