Base | Representation |
---|---|
bin | 11110110010010000111… |
… | …000000000000001110101 |
3 | 21111020121122001010010122 |
4 | 132302100320000001311 |
5 | 234130123423241132 |
6 | 4255512231101325 |
7 | 305562261424043 |
oct | 36622070000165 |
9 | 7436548033118 |
10 | 2115554508917 |
11 | 746224405733 |
12 | 2a2012b11845 |
13 | 12465a74b735 |
14 | 74571639393 |
15 | 3a06ca60912 |
hex | 1ec90e00075 |
2115554508917 has 2 divisors, whose sum is σ = 2115554508918. Its totient is φ = 2115554508916.
The previous prime is 2115554508887. The next prime is 2115554508923. The reversal of 2115554508917 is 7198054555112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1924520827441 + 191033681476 = 1387271^2 + 437074^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2115554508917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2115554508817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1057777254458 + 1057777254459.
It is an arithmetic number, because the mean of its divisors is an integer number (1057777254459).
Almost surely, 22115554508917 is an apocalyptic number.
It is an amenable number.
2115554508917 is a deficient number, since it is larger than the sum of its proper divisors (1).
2115554508917 is an equidigital number, since it uses as much as digits as its factorization.
2115554508917 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520000, while the sum is 53.
The spelling of 2115554508917 in words is "two trillion, one hundred fifteen billion, five hundred fifty-four million, five hundred eight thousand, nine hundred seventeen".
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