Search a number
-
+
211684797053 is a prime number
BaseRepresentation
bin1100010100100101100…
…1011010101001111101
3202020101200021212200122
43011021121122221331
511432012302001203
6241125135504325
721202514041502
oct3051131325175
9666350255618
10211684797053
1181858605174
12350389880a5
1316c67092082
14a361ccd4a9
15578e1d1538
hex314965aa7d

211684797053 has 2 divisors, whose sum is σ = 211684797054. Its totient is φ = 211684797052.

The previous prime is 211684797043. The next prime is 211684797119. The reversal of 211684797053 is 350797486112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 145842263449 + 65842533604 = 381893^2 + 256598^2 .

It is a cyclic number.

It is not a de Polignac number, because 211684797053 - 214 = 211684780669 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211684796986 and 211684797004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211684797043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105842398526 + 105842398527.

It is an arithmetic number, because the mean of its divisors is an integer number (105842398527).

It is a 1-persistent number, because it is pandigital, but 2⋅211684797053 = 423369594106 is not.

Almost surely, 2211684797053 is an apocalyptic number.

It is an amenable number.

211684797053 is a deficient number, since it is larger than the sum of its proper divisors (1).

211684797053 is an equidigital number, since it uses as much as digits as its factorization.

211684797053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 211684797053 in words is "two hundred eleven billion, six hundred eighty-four million, seven hundred ninety-seven thousand, fifty-three".