212001121100213 has 2 divisors, whose sum is σ = 212001121100214. Its totient is φ = 212001121100212.

The previous prime is 212001121100123. The next prime is 212001121100281. The reversal of 212001121100213 is 312001121100212.

It is a happy number.

Together with previous prime (212001121100123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 210562097734564 + 1439023365649 = 14510758^2 + 1199593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-212001121100213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212001121100191 and 212001121100200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212003121100213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106000560550106 + 106000560550107.

It is an arithmetic number, because the mean of its divisors is an integer number (106000560550107).

Almost surely, 2^{212001121100213} is an apocalyptic number.

It is an amenable number.

212001121100213 is a deficient number, since it is larger than the sum of its proper divisors (1).

212001121100213 is an equidigital number, since it uses as much as digits as its factorization.

212001121100213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 212001121100213 its reverse (312001121100212), we get a palindrome (524002242200425).

Subtracting 212001121100213 from its reverse (312001121100212), we obtain a palindrome (99999999999999).

The spelling of 212001121100213 in words is "two hundred twelve trillion, one billion, one hundred twenty-one million, one hundred thousand, two hundred thirteen".