Base | Representation |
---|---|
bin | 11110110110100000101… |
… | …001100010110100100100 |
3 | 21111200101101202110110000 |
4 | 132312200221202310210 |
5 | 234213443203401040 |
6 | 4301544511301300 |
7 | 306113255460516 |
oct | 36664051426444 |
9 | 7450341673400 |
10 | 2120114122020 |
11 | 748154172524 |
12 | 2a2a85b1a830 |
13 | 124c0629805b |
14 | 74885021bb6 |
15 | 3a237ec7130 |
hex | 1eda0a62d24 |
2120114122020 has 60 divisors (see below), whose sum is σ = 6650876528604. Its totient is φ = 565363765440.
The previous prime is 2120114122013. The next prime is 2120114122073. The reversal of 2120114122020 is 202214110212.
2120114122020 is a `hidden beast` number, since 21 + 20 + 11 + 412 + 202 + 0 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 1682603311104 + 437510810916 = 1297152^2 + 661446^2 .
It is a tau number, because it is divible by the number of its divisors (60).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 2120114121984 and 2120114122002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 654354591 + ... + 654357830.
Almost surely, 22120114122020 is an apocalyptic number.
2120114122020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2120114122020 is an abundant number, since it is smaller than the sum of its proper divisors (4530762406584).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2120114122020 is a wasteful number, since it uses less digits than its factorization.
2120114122020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1308712442 (or 1308712431 counting only the distinct ones).
The product of its (nonzero) digits is 128, while the sum is 18.
Adding to 2120114122020 its reverse (202214110212), we get a palindrome (2322328232232).
It can be divided in two parts, 21201 and 14122020, that added together give a triangular number (14143221 = T5318).
The spelling of 2120114122020 in words is "two trillion, one hundred twenty billion, one hundred fourteen million, one hundred twenty-two thousand, twenty".
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