Base | Representation |
---|---|
bin | 1001101001000010010100… |
… | …00011110111010101001111 |
3 | 2210001211000011020211020111 |
4 | 10310201022003313111033 |
5 | 10234330024440200421 |
6 | 113031410342300451 |
7 | 4315510345634344 |
oct | 464411203672517 |
9 | 83054004224214 |
10 | 21201201100111 |
11 | 683441934144a |
12 | 2464b27427727 |
13 | baa359689866 |
14 | 5342020c07cb |
15 | 26b75a227ee1 |
hex | 13484a0f754f |
21201201100111 has 2 divisors, whose sum is σ = 21201201100112. Its totient is φ = 21201201100110.
The previous prime is 21201201100067. The next prime is 21201201100133. The reversal of 21201201100111 is 11100110210212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21201201100111 - 213 = 21201201091919 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21201201100091 and 21201201100100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21201201100181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600600550055 + 10600600550056.
It is an arithmetic number, because the mean of its divisors is an integer number (10600600550056).
Almost surely, 221201201100111 is an apocalyptic number.
21201201100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
21201201100111 is an equidigital number, since it uses as much as digits as its factorization.
21201201100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 21201201100111 its reverse (11100110210212), we get a palindrome (32301311310323).
The spelling of 21201201100111 in words is "twenty-one trillion, two hundred one billion, two hundred one million, one hundred thousand, one hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •