Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …0010010110010010101 |
3 | 202021020120022001201021 |
4 | 3011130332102302111 |
5 | 11433200341400003 |
6 | 241221511201141 |
7 | 21213612505555 |
oct | 3053476226225 |
9 | 667216261637 |
10 | 212013231253 |
11 | 81a06a3a69a |
12 | 3510a9761b1 |
13 | 16cba137235 |
14 | a393785165 |
15 | 57ace5a2bd |
hex | 315cf92c95 |
212013231253 has 2 divisors, whose sum is σ = 212013231254. Its totient is φ = 212013231252.
The previous prime is 212013231229. The next prime is 212013231257. The reversal of 212013231253 is 352132310212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199222073649 + 12791157604 = 446343^2 + 113098^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212013231253 is a prime.
It is a super-2 number, since 2×2120132312532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212013231257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006615626 + 106006615627.
It is an arithmetic number, because the mean of its divisors is an integer number (106006615627).
Almost surely, 2212013231253 is an apocalyptic number.
It is an amenable number.
212013231253 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013231253 is an equidigital number, since it uses as much as digits as its factorization.
212013231253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 212013231253 its reverse (352132310212), we get a palindrome (564145541465).
The spelling of 212013231253 in words is "two hundred twelve billion, thirteen million, two hundred thirty-one thousand, two hundred fifty-three".
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