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21202112000107 is a prime number
BaseRepresentation
bin1001101001000100000000…
…10110101011000001101011
32210001220100122021100010101
410310202000112223001223
510234333411133000412
6113032041002130231
74315542046311433
oct464420026530153
983056318240111
1021202112000107
116834846539065
1224651404b0977
13baa4732cb63c
1453428b0772c3
1526b7b01a9457
hex1348805ab06b

21202112000107 has 2 divisors, whose sum is σ = 21202112000108. Its totient is φ = 21202112000106.

The previous prime is 21202112000071. The next prime is 21202112000143. The reversal of 21202112000107 is 70100021120212.

Together with previous prime (21202112000071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (21202112000071) and next prime (21202112000143).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21202112000107 is a prime.

It is a super-2 number, since 2×212021120001072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21202112000177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601056000053 + 10601056000054.

It is an arithmetic number, because the mean of its divisors is an integer number (10601056000054).

Almost surely, 221202112000107 is an apocalyptic number.

21202112000107 is a deficient number, since it is larger than the sum of its proper divisors (1).

21202112000107 is an equidigital number, since it uses as much as digits as its factorization.

21202112000107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 21202112000107 its reverse (70100021120212), we get a palindrome (91302133120319).

The spelling of 21202112000107 in words is "twenty-one trillion, two hundred two billion, one hundred twelve million, one hundred seven", and thus it is an aban number.