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212110010001143 is a prime number
BaseRepresentation
bin110000001110100110110101…
…110011001010011011110111
31000211000112000021221020201122
4300032212311303022123313
5210300202300030014033
62031041554323414155
762451304532033402
oct6016466563123367
91024015007836648
10212110010001143
1161648393a49271
121b95841122435b
139147b7126a8a7
143a54271c6ad39
15197c704dd0a98
hexc0e9b5cca6f7

212110010001143 has 2 divisors, whose sum is σ = 212110010001144. Its totient is φ = 212110010001142.

The previous prime is 212110010001011. The next prime is 212110010001151. The reversal of 212110010001143 is 341100010011212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 212110010001143 - 224 = 212109993223927 is a prime.

It is a super-2 number, since 2×2121100100011432 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212110010081143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106055005000571 + 106055005000572.

It is an arithmetic number, because the mean of its divisors is an integer number (106055005000572).

Almost surely, 2212110010001143 is an apocalyptic number.

212110010001143 is a deficient number, since it is larger than the sum of its proper divisors (1).

212110010001143 is an equidigital number, since it uses as much as digits as its factorization.

212110010001143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 212110010001143 its reverse (341100010011212), we get a palindrome (553210020012355).

The spelling of 212110010001143 in words is "two hundred twelve trillion, one hundred ten billion, ten million, one thousand, one hundred forty-three".