Base | Representation |
---|---|
bin | 110000001110100110110101… |
… | …110011011101111101110111 |
3 | 1000211000112000022002022110121 |
4 | 300032212311303131331313 |
5 | 210300202300040044033 |
6 | 2031041554325232411 |
7 | 62451304532515546 |
oct | 6016466563357567 |
9 | 1024015008068417 |
10 | 212110010081143 |
11 | 61648393aa3389 |
12 | 1b958411262707 |
13 | 9147b71298125 |
14 | 3a54271c8c15d |
15 | 197c704de962d |
hex | c0e9b5cddf77 |
212110010081143 has 2 divisors, whose sum is σ = 212110010081144. Its totient is φ = 212110010081142.
The previous prime is 212110010081113. The next prime is 212110010081149. The reversal of 212110010081143 is 341180010011212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212110010081143 - 241 = 209910986825591 is a prime.
It is a super-3 number, since 3×2121100100811433 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212110010081149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106055005040571 + 106055005040572.
It is an arithmetic number, because the mean of its divisors is an integer number (106055005040572).
Almost surely, 2212110010081143 is an apocalyptic number.
212110010081143 is a deficient number, since it is larger than the sum of its proper divisors (1).
212110010081143 is an equidigital number, since it uses as much as digits as its factorization.
212110010081143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 25.
Adding to 212110010081143 its reverse (341180010011212), we get a palindrome (553290020092355).
The spelling of 212110010081143 in words is "two hundred twelve trillion, one hundred ten billion, ten million, eighty-one thousand, one hundred forty-three".
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