Base | Representation |
---|---|
bin | 110000001110100110110110… |
… | …011001010110010011010101 |
3 | 1000211000112000222202210222021 |
4 | 300032212312121112103111 |
5 | 210300202310110324341 |
6 | 2031041555322133141 |
7 | 62451305013104323 |
oct | 6016466631262325 |
9 | 1024015028683867 |
10 | 212110020011221 |
11 | 61648399665a62 |
12 | 1b9584146511b1 |
13 | 9147b73363c07 |
14 | 3a54273314d13 |
15 | 197c705c0b9d1 |
hex | c0e9b66564d5 |
212110020011221 has 2 divisors, whose sum is σ = 212110020011222. Its totient is φ = 212110020011220.
The previous prime is 212110020011207. The next prime is 212110020011249. The reversal of 212110020011221 is 122110020011212.
212110020011221 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 183959716080625 + 28150303930596 = 13563175^2 + 5305686^2 .
It is a cyclic number.
It is not a de Polignac number, because 212110020011221 - 215 = 212110019978453 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212110020011195 and 212110020011204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212110020011261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106055010005610 + 106055010005611.
It is an arithmetic number, because the mean of its divisors is an integer number (106055010005611).
Almost surely, 2212110020011221 is an apocalyptic number.
It is an amenable number.
212110020011221 is a deficient number, since it is larger than the sum of its proper divisors (1).
212110020011221 is an equidigital number, since it uses as much as digits as its factorization.
212110020011221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 212110020011221 its reverse (122110020011212), we get a palindrome (334220040022433).
Subtracting from 212110020011221 its reverse (122110020011212), we obtain a palindrome (90000000000009).
The spelling of 212110020011221 in words is "two hundred twelve trillion, one hundred ten billion, twenty million, eleven thousand, two hundred twenty-one".
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