Base | Representation |
---|---|
bin | 11110110111011100101… |
… | …011010100100111101111 |
3 | 21111202222120210101200001 |
4 | 132313130223110213233 |
5 | 234223024013033403 |
6 | 4302232445045131 |
7 | 306150234616453 |
oct | 36673453244757 |
9 | 7452876711601 |
10 | 2121121221103 |
11 | 7486206a4a15 |
12 | 2a31072567a7 |
13 | 125036b1c581 |
14 | 7493ca9a663 |
15 | 3a29660bc1d |
hex | 1eddcad49ef |
2121121221103 has 2 divisors, whose sum is σ = 2121121221104. Its totient is φ = 2121121221102.
The previous prime is 2121121221097. The next prime is 2121121221151. The reversal of 2121121221103 is 3011221211212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2121121221103 - 213 = 2121121212911 is a prime.
It is a super-2 number, since 2×21211212211032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121121227103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060560610551 + 1060560610552.
It is an arithmetic number, because the mean of its divisors is an integer number (1060560610552).
Almost surely, 22121121221103 is an apocalyptic number.
2121121221103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121121221103 is an equidigital number, since it uses as much as digits as its factorization.
2121121221103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2121121221103 its reverse (3011221211212), we get a palindrome (5132342432315).
The spelling of 2121121221103 in words is "two trillion, one hundred twenty-one billion, one hundred twenty-one million, two hundred twenty-one thousand, one hundred three".
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