Search a number
-
+
21212101122133 is a prime number
BaseRepresentation
bin1001101001010110100111…
…10000001001100001010101
32210002212010210120022110211
410310223103300021201111
510240014340341402013
6113040412115445421
74316344432406245
oct464532360114125
983085123508424
1021212101122133
1168390020a3309
1224670698b6871
13bab3a597a72c
145349579a7b25
1526bb9711923d
hex134ad3c09855

21212101122133 has 2 divisors, whose sum is σ = 21212101122134. Its totient is φ = 21212101122132.

The previous prime is 21212101122109. The next prime is 21212101122167. The reversal of 21212101122133 is 33122110121212.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20411537875569 + 800563246564 = 4517913^2 + 894742^2 .

It is a cyclic number.

It is not a de Polignac number, because 21212101122133 - 213 = 21212101113941 is a prime.

It is a super-3 number, since 3×212121011221333 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21212107122133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606050561066 + 10606050561067.

It is an arithmetic number, because the mean of its divisors is an integer number (10606050561067).

Almost surely, 221212101122133 is an apocalyptic number.

It is an amenable number.

21212101122133 is a deficient number, since it is larger than the sum of its proper divisors (1).

21212101122133 is an equidigital number, since it uses as much as digits as its factorization.

21212101122133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 21212101122133 its reverse (33122110121212), we get a palindrome (54334211243345).

The spelling of 21212101122133 in words is "twenty-one trillion, two hundred twelve billion, one hundred one million, one hundred twenty-two thousand, one hundred thirty-three".