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21212103121309 is a prime number
BaseRepresentation
bin1001101001010110100111…
…10111110001100110011101
32210002212010221022212211101
410310223103313301212131
510240014341344340214
6113040412230353101
74316344455403612
oct464532367614635
983085127285741
1021212103121309
116839003239321
12246706a4bb791
13bab3a61ca689
14534957d68509
1526bb973b1774
hex134ad3df199d

21212103121309 has 2 divisors, whose sum is σ = 21212103121310. Its totient is φ = 21212103121308.

The previous prime is 21212103121193. The next prime is 21212103121337. The reversal of 21212103121309 is 90312130121212.

It is an a-pointer prime, because the next prime (21212103121337) can be obtained adding 21212103121309 to its sum of digits (28).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20371953060900 + 840150060409 = 4513530^2 + 916597^2 .

It is a cyclic number.

It is not a de Polignac number, because 21212103121309 - 221 = 21212101024157 is a prime.

It is a super-3 number, since 3×212121031213093 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21212103121009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606051560654 + 10606051560655.

It is an arithmetic number, because the mean of its divisors is an integer number (10606051560655).

Almost surely, 221212103121309 is an apocalyptic number.

It is an amenable number.

21212103121309 is a deficient number, since it is larger than the sum of its proper divisors (1).

21212103121309 is an equidigital number, since it uses as much as digits as its factorization.

21212103121309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 28.

The spelling of 21212103121309 in words is "twenty-one trillion, two hundred twelve billion, one hundred three million, one hundred twenty-one thousand, three hundred nine".