Base | Representation |
---|---|
bin | 1100010110001110101… |
… | …0010011010100111111 |
3 | 202021112101102101222021 |
4 | 3011203222103110333 |
5 | 11433413102243403 |
6 | 241241000101011 |
7 | 21216444262045 |
oct | 3054352232477 |
9 | 667471371867 |
10 | 212125431103 |
11 | 81a64304043 |
12 | 35140464767 |
13 | 1700745c991 |
14 | a3a4630395 |
15 | 57b7c1e8bd |
hex | 3163a9353f |
212125431103 has 2 divisors, whose sum is σ = 212125431104. Its totient is φ = 212125431102.
The previous prime is 212125431059. The next prime is 212125431121. The reversal of 212125431103 is 301134521212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212125431103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212125431143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106062715551 + 106062715552.
It is an arithmetic number, because the mean of its divisors is an integer number (106062715552).
Almost surely, 2212125431103 is an apocalyptic number.
212125431103 is a deficient number, since it is larger than the sum of its proper divisors (1).
212125431103 is an equidigital number, since it uses as much as digits as its factorization.
212125431103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 212125431103 its reverse (301134521212), we get a palindrome (513259952315).
The spelling of 212125431103 in words is "two hundred twelve billion, one hundred twenty-five million, four hundred thirty-one thousand, one hundred three".
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