Base | Representation |
---|---|
bin | 11110110111100101000… |
… | …000100111001111101111 |
3 | 21111210100022211220220021 |
4 | 132313211000213033233 |
5 | 234223320310121033 |
6 | 4302254401303011 |
7 | 306153553112026 |
oct | 36674500471757 |
9 | 7453308756807 |
10 | 2121261020143 |
11 | 7486925aa011 |
12 | 2a3146034a67 |
13 | 125059a892b5 |
14 | 7495348b8bd |
15 | 3a2a3a23b2d |
hex | 1ede50273ef |
2121261020143 has 2 divisors, whose sum is σ = 2121261020144. Its totient is φ = 2121261020142.
The previous prime is 2121261020111. The next prime is 2121261020159. The reversal of 2121261020143 is 3410201621212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2121261020143 - 25 = 2121261020111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121261020843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060630510071 + 1060630510072.
It is an arithmetic number, because the mean of its divisors is an integer number (1060630510072).
Almost surely, 22121261020143 is an apocalyptic number.
2121261020143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121261020143 is an equidigital number, since it uses as much as digits as its factorization.
2121261020143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 2121261020143 its reverse (3410201621212), we get a palindrome (5531462641355).
The spelling of 2121261020143 in words is "two trillion, one hundred twenty-one billion, two hundred sixty-one million, twenty thousand, one hundred forty-three".
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