Base | Representation |
---|---|
bin | 1100010110010000101… |
… | …1100000001000011101 |
3 | 202021112222210120111221 |
4 | 3011210023200020131 |
5 | 11433422314244201 |
6 | 241241510413341 |
7 | 21216611250565 |
oct | 3054413401035 |
9 | 667488716457 |
10 | 212134134301 |
11 | 81a69208971 |
12 | 35143361251 |
13 | 170091b91bb |
14 | a3a5857da5 |
15 | 57b888d4a1 |
hex | 31642e021d |
212134134301 has 2 divisors, whose sum is σ = 212134134302. Its totient is φ = 212134134300.
The previous prime is 212134134287. The next prime is 212134134307. The reversal of 212134134301 is 103431431212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132604494201 + 79529640100 = 364149^2 + 282010^2 .
It is a cyclic number.
It is not a de Polignac number, because 212134134301 - 217 = 212134003229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212134134307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106067067150 + 106067067151.
It is an arithmetic number, because the mean of its divisors is an integer number (106067067151).
Almost surely, 2212134134301 is an apocalyptic number.
It is an amenable number.
212134134301 is a deficient number, since it is larger than the sum of its proper divisors (1).
212134134301 is an equidigital number, since it uses as much as digits as its factorization.
212134134301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 212134134301 its reverse (103431431212), we get a palindrome (315565565513).
It can be divided in two parts, 21213 and 4134301, that added together give a palindrome (4155514).
The spelling of 212134134301 in words is "two hundred twelve billion, one hundred thirty-four million, one hundred thirty-four thousand, three hundred one".
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