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21213543315103 = 39671534736793
BaseRepresentation
bin1001101001011001010011…
…01101101011011010011111
32210002222212022022022022021
410310230221231223122133
510240030314042040403
6113041211155001011
74316425244012416
oct464545155533237
983088768268267
1021213543315103
116839682190227
1224673b0899167
13bab5756acc59
14534a5334047d
1526bc2da458bd
hex134b29b6b69f

21213543315103 has 4 divisors (see below), whose sum is σ = 21214078091568. Its totient is φ = 21213008538640.

The previous prime is 21213543315073. The next prime is 21213543315143. The reversal of 21213543315103 is 30151334531212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21213543315103 - 213 = 21213543306911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21213543315143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 267328726 + ... + 267408067.

It is an arithmetic number, because the mean of its divisors is an integer number (5303519522892).

Almost surely, 221213543315103 is an apocalyptic number.

21213543315103 is a deficient number, since it is larger than the sum of its proper divisors (534776465).

21213543315103 is an equidigital number, since it uses as much as digits as its factorization.

21213543315103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 534776464.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 21213543315103 its reverse (30151334531212), we get a palindrome (51364877846315).

The spelling of 21213543315103 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, one hundred three".

Divisors: 1 39671 534736793 21213543315103