Base | Representation |
---|---|
bin | 1100010110100010110… |
… | …1101101100100111011 |
3 | 202021202021221200022022 |
4 | 3011220231231210323 |
5 | 11434101303224011 |
6 | 241253225145055 |
7 | 21221524014122 |
oct | 3055055554473 |
9 | 667667850268 |
10 | 212210211131 |
11 | 81aa814a586 |
12 | 3516492b18b |
13 | 1701bba4989 |
14 | a3b19bcab9 |
15 | 57c03b98db |
hex | 3168b6d93b |
212210211131 has 2 divisors, whose sum is σ = 212210211132. Its totient is φ = 212210211130.
The previous prime is 212210211119. The next prime is 212210211133. The reversal of 212210211131 is 131112012212.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212210211131 is a prime.
It is a super-2 number, since 2×2122102111312 (a number of 23 digits) contains 22 as substring.
Together with 212210211133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (212210211133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106105105565 + 106105105566.
It is an arithmetic number, because the mean of its divisors is an integer number (106105105566).
Almost surely, 2212210211131 is an apocalyptic number.
212210211131 is a deficient number, since it is larger than the sum of its proper divisors (1).
212210211131 is an equidigital number, since it uses as much as digits as its factorization.
212210211131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 212210211131 its reverse (131112012212), we get a palindrome (343322223343).
The spelling of 212210211131 in words is "two hundred twelve billion, two hundred ten million, two hundred eleven thousand, one hundred thirty-one".
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