2122211100041 has 2 divisors, whose sum is σ = 2122211100042. Its totient is φ = 2122211100040.

The previous prime is 2122211100029. The next prime is 2122211100043. The reversal of 2122211100041 is 1400011122212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1897175664400 + 225035435641 = 1377380^2 + 474379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2122211100041 is a prime.

Together with 2122211100043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2122211099992 and 2122211100019.

It is not a weakly prime, because it can be changed into another prime (2122211100043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061105550020 + 1061105550021.

It is an arithmetic number, because the mean of its divisors is an integer number (1061105550021).

Almost surely, 2^{2122211100041} is an apocalyptic number.

It is an amenable number.

2122211100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2122211100041 is an equidigital number, since it uses as much as digits as its factorization.

2122211100041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 2122211100041 its reverse (1400011122212), we get a palindrome (3522222222253).

The spelling of 2122211100041 in words is "two trillion, one hundred twenty-two billion, two hundred eleven million, one hundred thousand, forty-one".