Base | Representation |
---|---|
bin | 110000010000010001010011… |
… | …110111101010100100000110 |
3 | 1000211102110002112022101002112 |
4 | 300100101103313222210012 |
5 | 210304040412232144032 |
6 | 2031210302314141022 |
7 | 62462462523433451 |
oct | 6020212367524406 |
9 | 1024373075271075 |
10 | 212224331131142 |
11 | 616919192792a0 |
12 | 1b9765b7121772 |
13 | 915588ca74845 |
14 | 3a599d8cb8498 |
15 | 19806965331b2 |
hex | c10453dea906 |
212224331131142 has 32 divisors (see below), whose sum is σ = 349079995630080. Its totient is φ = 95964659693280.
The previous prime is 212224331131117. The next prime is 212224331131171. The reversal of 212224331131142 is 241131133422212.
It is a junction number, because it is equal to n+sod(n) for n = 212224331131099 and 212224331131108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34084709 + ... + 39827327.
It is an arithmetic number, because the mean of its divisors is an integer number (10908749863440).
Almost surely, 2212224331131142 is an apocalyptic number.
212224331131142 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
212224331131142 is a deficient number, since it is larger than the sum of its proper divisors (136855664498938).
212224331131142 is a wasteful number, since it uses less digits than its factorization.
212224331131142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5751356.
The product of its digits is 13824, while the sum is 32.
Adding to 212224331131142 its reverse (241131133422212), we get a palindrome (453355464553354).
The spelling of 212224331131142 in words is "two hundred twelve trillion, two hundred twenty-four billion, three hundred thirty-one million, one hundred thirty-one thousand, one hundred forty-two".
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