Base | Representation |
---|---|
bin | 11110111001001111101… |
… | …010110011000100111111 |
3 | 21111221222001000001210001 |
4 | 132321033222303010333 |
5 | 234241001404313201 |
6 | 4303152123255131 |
7 | 306246112121143 |
oct | 36711752630477 |
9 | 7457861001701 |
10 | 2123050463551 |
11 | 749420703366 |
12 | 2a356537a4a7 |
13 | 125283721354 |
14 | 74a82db7223 |
15 | 3a35ab94301 |
hex | 1ee4fab313f |
2123050463551 has 2 divisors, whose sum is σ = 2123050463552. Its totient is φ = 2123050463550.
The previous prime is 2123050463549. The next prime is 2123050463623. The reversal of 2123050463551 is 1553640503212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2123050463551 - 21 = 2123050463549 is a prime.
Together with 2123050463549, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 2123050463551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2123050463531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061525231775 + 1061525231776.
It is an arithmetic number, because the mean of its divisors is an integer number (1061525231776).
Almost surely, 22123050463551 is an apocalyptic number.
2123050463551 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123050463551 is an equidigital number, since it uses as much as digits as its factorization.
2123050463551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 2123050463551 its reverse (1553640503212), we get a palindrome (3676690966763).
The spelling of 2123050463551 in words is "two trillion, one hundred twenty-three billion, fifty million, four hundred sixty-three thousand, five hundred fifty-one".
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